1041B - Buying a TV Set - CodeForces Solution


math *1000

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Python Code:

import math
a, b, c, d = map(int, input().split())
g = math.gcd(c,d)
c /= g
d /= g
print(int(min(a/c, b/d)))

C++ Code:

/******************************************************************************

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#include <bits/stdc++.h>

using namespace std;
typedef long long ll;

int main()
{
    ll a,b,x,y;
    cin >> a >> b >> x >> y;
    ll gcd1 = __gcd(y,x);
    x=x/gcd1;
    y=y/gcd1;
    ll ans = a/x;
    ll ans2 = b/y;
    ans = min(ans,ans2);

    cout << ans << endl;
    return 0;
}


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